C++/coding skills
[C++] 쓰레기값 거르기(아주 작은값) numeric_limits
화이팅입미다
2020. 12. 4. 16:38
numeric_limits 클래스
구문
template <class Type>
class numeric_limits
epsilon
함수는 1과 데이터 형식에 대해 나타낼 수 있는 1보다 큰 가장 작은 값 사이의 차이를 반환
예제
// numeric_limits_epsilon.cpp
// compile with: /EHsc
#include <iostream>
#include <limits>
using namespace std;
int main( )
{
cout << "The difference between 1 and the smallest "
<< "value greater than 1" << endl
<< "for float objects is: "
<< numeric_limits<float>::epsilon( ) << endl;
cout << "The difference between 1 and the smallest "
<< "value greater than 1" << endl
<< "for double objects is: "
<< numeric_limits<double>::epsilon( ) << endl;
cout << "The difference between 1 and the smallest "
<< "value greater than 1" << endl
<< "for long double objects is: "
<< numeric_limits<long double>::epsilon( ) << endl;
}
output
The difference between 1 and the smallest value greater than 1
for float objects is: 1.19209e-007
The difference between 1 and the smallest value greater than 1
for double objects is: 2.22045e-016
The difference between 1 and the smallest value greater than 1
for long double objects is: 2.22045e-016
사용 예시
float f_tmp;
if(fabsf(f_tmp) < std::numeric_limits<float>::epsilon()) return;
이런식으로 쓰레기값을 거를 수 있다